What is the new horsepower required if the pump is moving 750 gpm and has a head of 170 feet?

To determine the required horsepower for a pump moving 750 gallons per minute (gpm) with a head of 170 feet, we can use the formula for hydraulic horsepower:

[

\text{Horsepower} = \frac{(gpm \times \text{Head in feet})}{3960}

]

In this case, substituting the given values into the formula:

1. Flow Rate: 750 gpm

2. Head: 170 feet

Calculating the hydraulic horsepower:

[

\text{Horsepower} = \frac{(750 , \text{gpm} \times 170 , \text{feet})}{3960}

]

Carrying out the multiplication:

[

750 \times 170 = 127500

]

Then dividing by 3960:

[

\text{Horsepower} = \frac{127500}{3960} \approx 32.2

]

Since this calculation gives a value of approximately 32.2, the necessary adjustments for efficiency and other losses in a real-world scenario will increase this number. However, if the question is asking for simple hydraulic horsepower without accounting for these factors, option A could