If 10 gallons of a 12% solution is mixed with 50 gallons of a 0.8% solution, what is the percent strength of the resultant mixed solution?

Study for the Texas Wastewater Class A Exam. Enjoy flashcards and multiple choice questions, each with hints and explanations. Prepare effectively for your exam!

To find the percent strength of the resultant mixed solution, you first need to determine the total amount of the substance in each solution and then the total volume of the mixture.

Start by calculating the amount of the active ingredient in both solutions:

  1. For the 10 gallons of a 12% solution:
  • The amount of the substance = 10 gallons * 0.12 = 1.2 gallons.
  1. For the 50 gallons of a 0.8% solution:
  • The amount of the substance = 50 gallons * 0.008 = 0.4 gallons.

Next, add these two amounts together to get the total amount of the active ingredient in the mixture:

  • Total active ingredient = 1.2 gallons + 0.4 gallons = 1.6 gallons.

Next, find the total volume of the mixed solution:

  • Total volume = 10 gallons + 50 gallons = 60 gallons.

Now, to find the percent strength of the resultant mixed solution, use the formula for percent concentration:

  • Percent strength = (Total amount of substance / Total volume) * 100.

Plugging in the values:

  • Percent strength = (1.6 gallons / 60 gallons)
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